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-rwxr-xr-xreport/paper.md2
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@@ -514,4 +514,6 @@ We know that $S\boldsymbol{u\textsubscript{i}} = \lambda \textsubscript{i}\bolds
From here it follows that AA\textsuperscript{T} and A\textsuperscript{T}A have the same eigenvalues and their eigenvectors follow the relationship $\boldsymbol{u\textsubscript{i}} = A\boldsymbol{v\textsubscript{i}}$
+# Code
+All code and \LaTeX sources are available at [https://git.skozl.com/e4-pattern/](https://git.skozl.com/e4-pattern/).