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| author | Vasil Zlatanov <v@skozl.com> | 2017-02-20 15:06:24 +0000 |
|---|---|---|
| committer | Vasil Zlatanov <v@skozl.com> | 2017-02-20 15:06:24 +0000 |
| commit | f374fbf663a27d6a78c8fda6f160d39d4945e82c (patch) | |
| tree | 4f30bfd61523f0ce9cdde7cb6d15b8cb1a91126f /coursework17 | |
| parent | abcd65d98b8a4830673d53eaa9665ad195b70b03 (diff) | |
| download | e2-matlab-f374fbf663a27d6a78c8fda6f160d39d4945e82c.tar.gz e2-matlab-f374fbf663a27d6a78c8fda6f160d39d4945e82c.tar.bz2 e2-matlab-f374fbf663a27d6a78c8fda6f160d39d4945e82c.zip | |
Exact solution hint
Diffstat (limited to 'coursework17')
| -rw-r--r-- | coursework17/ralston.m | 1 |
1 files changed, 1 insertions, 0 deletions
diff --git a/coursework17/ralston.m b/coursework17/ralston.m index d910442..7ed4ad3 100644 --- a/coursework17/ralston.m +++ b/coursework17/ralston.m @@ -10,6 +10,7 @@ function [time_array, Vout_array] = ralston(R, L, Vin, current_initial, step, t_ % Given the input voltage as a function of time we can express % dI/dt (dcurrent_dt) as a function of time as well (given R and L) + % NOTE we can use the integrating factor to find exact solution dcurrent_dt = @(t, I) (Vin(t) - I*R)/L; % Loop as many times as step allows and: |